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刚开始,根据我的想法,这个很简单嘛,上sql语句MYSQL必读
delete from zqzrdp where tel in (select min(dpxx_id) from zqzrdp group by tel having count(tel)>1);
执行,报错!!~!~MYSQL必读
MYSQL必读
异常意为：你不能指定目标表的更新在FROM子句.傻了,MySQL 这样写,不行,让人郁闷.MYSQL必读
难倒只能分步操作,蛋疼MYSQL必读
以下是网友写的,同样是坑爹的代码,我机器上运行不了.MYSQL必读
1. 查询需要删除的记录,会保留一条记录.MYSQL必读
select a.id,a.subject,a.RECEIVER from test1 a left join (select c.subject,c.RECEIVER ,max(c.id) as bid from test1 c where status=0 GROUP BY RECEIVER,SUBJECT having count(1) >1) b on a.id< b.bid where a.subject=b.subject and a.RECEIVER = b.RECEIVER and a.id < b.bid
2. 删除重复记录,只保留一条记录.注意,subject,RECEIVER 要索引,否则会很慢的.MYSQL必读
delete a from test1 a, (select c.subject,c.RECEIVER ,max(c.id) as bid from test1 c where status=0 GROUP BY RECEIVER,SUBJECT having count(1) >1) b where a.subject=b.subject and a.RECEIVER = b.RECEIVER and a.id < b.bid;
3. 查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断MYSQL必读
select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
4. 删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录MYSQL必读
delete from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)
5.删除表中多余的重复记录(多个字段),只留有rowid最小的记录MYSQL必读
delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
看来想偷懒使用一句命令完成这个事好像不太显示,还是老老实实的分步处理吧,思路先建立复制一个临时表,然后对比临时表内的数据,删除主表里的数据MYSQL必读
alter table tableName add autoID int auto_increment not null; create table tmp select min(autoID) as autoID from tableName group by Name,Address; create table tmp2 select tableName.* from tableName,tmp where tableName.autoID = tmp.autoID; drop table tableName; rename table tmp2 to tableName;
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